3x^2=-24x-4

Solution for 3x^2=-24x-4 equation:

3x^2=-24x-4

We move all terms to the left:

3x^2-(-24x-4)=0

We get rid of parentheses

3x^2+24x+4=0

a = 3; b = 24; c = +4;
Δ = b2-4ac
Δ = 242-4·3·4
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{33}}{2*3}=\frac{-24-4\sqrt{33}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{33}}{2*3}=\frac{-24+4\sqrt{33}}{6}
$